MySQL - Use Distinct in Where

Question

I have am working with 2 columns, one that should be unique but has duplicates that i want to remove and one column that i need a count of the duplicates. I have the second half of the equation figured out finally, but i still need to figure out how to remove the duplicates from the first column.

SELECT map.newvalue as 'Model of Phone', Count(*) as 'Number of Phones'
FROM items i, hosts h, history_uint huint, mappings map
WHERE h.hostid=i.hostid AND h.name='$Hosts' AND i.itemid=huint.itemid AND i.valuemapid=map.valuemapid AND huint.value=map.value AND i.name LIKE '%Model of the Phone'
GROUP BY map.newvalue
ORDER BY 'Item Name' DESC
LIMIT 100;

The table.column that i am getting duplicate values from is i.name . Sorry if my query looks awful, I am just an IT guy pretending to know SQL. Thank you for the assist!

Incase anyone else looks at this later in life, i am working on collecting phone models from Call Manager via SNMP and Zabbix and displaying it in Grafana.

Answer 1

You can not use distinct in where clause but you can use group by for multiple column Try with this

SELECT map.newvalue as 'Model of Phone', Count(*) as 'Number of Phones'
FROM items i, hosts h, history_uint huint, mappings map
WHERE h.hostid=i.hostid AND h.name='$Hosts' AND i.itemid=huint.itemid AND i.valuemapid=map.valuemapid AND huint.value=map.value AND i.name LIKE '%Model of the Phone'
GROUP BY map.newvalue, i.name
ORDER BY 'Item Name' DESC
LIMIT 100;

It will change your result a bit because of adding extra filed in group by but it will give you unique name and newvalue result.

Hope this will help you.