Plz suggest how to create dictionary from the following file contetns
2,20190327.1.csv.gz
3,20190327.23.csv.gz
4,20190327.21302.csv.gz
2,20190327.24562.csv.gz
my required output is
{2:20190327.1.csv.gz:982, 3:20190327.23.csv.gz, 4:20190327.21302.csv.gz, 2:20190327.24562.csv.gz}
I am new to python and I tried below code but It is not working. Please suggest
from __future__ import print_function
import csv
file = '/tmp/.fileA'
with open(file) as fh:
rd = csv.DictReader(fh, delimiter=',')
for row in rd:
print(row)
The problem is because the DictReader
thinks first row is field mapping, so number 2 will be used as key for next rows. Also, you can't use same key twice, hence one of the situations where 2 is used as key will be overwritten.
import csv
file = 'data.csv'
my_dict = {}
with open(file) as fh:
rd = csv.reader(fh, delimiter=',')
for row in rd:
my_dict[row[0]] = row[1]
print(my_dict)
Output:
$ python3 reader.py
{'2': '20190327.24562.csv.gz', '3': '20190327.23.csv.gz', '4': '20190327.21302.csv.gz'}
You could use defaultdict
from collections
to handle the unique keys,
The csv file,
$ cat some.csv
2,20190327.1.csv.gz
3,20190327.23.csv.gz
4,20190327.21302.csv.gz
2,20190327.24562.csv.gz
$ cat mkdict.py
import csv
from collections import defaultdict
import pprint
d = defaultdict(list)
with open('some.csv') as csvfile:
reader = csv.reader(csvfile, delimiter=',')
for row in reader:
if row: # taking care for empty lines :)
key, value = row
d[key].append(value)
pprint.pprint(dict(d))
And the output,
$ python mkdict.py
{'2': ['20190327.1.csv.gz', '20190327.24562.csv.gz'],
'3': ['20190327.23.csv.gz'],
'4': ['20190327.21302.csv.gz']}
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