Modify the function to return true if both arguments are true, and return false otherwise

Question

Keep getting Uncaught SyntaxError: Missing catch or finally after try

Why is this wrong?

function areBothTrue(bool1, bool2) {
  `return bool1 && bool2;`
}

}


console.log(areBothTrue(true, false), '<-- should be false');
console.log(areBothTrue(true, true), '<-- should be true');

Answer 1

Your code isn't complete. And the use of ` isn't required.

Here's the correct command

function areBothTrue(bool1, bool2) {
  if (bool1 && bool2){
    return true
  }
  else{
    return false
  }
}

console.log(areBothTrue(true, false), '<-- should be false');
console.log(areBothTrue(true, true), '<-- should be true');

Answer 2

Your code looks fine for me, instead of the extra curly bracket, which goes after the function definition and backticks surrounded return statement function areBothTrue(bool1, bool2) { return bool1 && bool2; } function areBothTrue(bool1, bool2) { return bool1 && bool2; } . It works just fine, you could check yourself putting it in a browser, for example, chrome console.

`const areBothTrue = function(bool1, bool2) { return bool1 && bool2; };

console.log(areBothTrue(true, false));` Probably your error goes from another part of the code you didn't post. Cheers