How to list daemon (services) process in linux, as with psutil?

Question

I am trying to print the current running services (daemon process?) in linux using psutil

In windows, using psutil I can get the currently running services with this code:

def log(self):
        win_sev = set()
        for sev in psutil.win_service_iter():
            if sev.status() == psutil.STATUS_RUNNING:
                win_sev.add(sev.display_name())
        return win_sev

I want to get the same effect in linux, I tried using the subprocess module and POPEN

 command = ["service", "--status-all"]  # the shell command
 p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=None)        
 result = p.communicate()[0]
 print result

However I would like to know if I can get the same result using psutil, I tried using the

psutil.pids()

But this only shows

python
init
bash

But when I run service --status-all I get a much bigger list including apache,sshd....

Thanks

Answer 1

^{The service command in WSL shows Windows services. As we've determined (in in-comment discussion) that you're trying to list Linux services, and using WSL only as a test platform, this answer is written to apply to the majority of Linux distributions, rather than to WSL.}

---

The following will work on Linux distros using systemd as their init system (this applies to most modern distros -- including current releases of Arch, NixOS, Fedora, RHEL, CentOS, Debian, Ubuntu, etc). It will not work on WSL -- at least, not the version you quoted, which does not appear to be using systemd as its init system.

#!/usr/bin/env python

import re
import psutil

def log_running_services():
    known_cgroups = set()
    for pid in psutil.pids():
        try:
            cgroups = open('/proc/%d/cgroup' % pid, 'r').read()
        except IOError:
            continue # may have exited since we read the listing, or may not have permissions
        systemd_name_match = re.search('^1:name=systemd:(/.+)$', cgroups, re.MULTILINE)
        if systemd_name_match is None:
            continue # not in a systemd-maintained cgroup
        systemd_name = systemd_name_match.group(1)
        if systemd_name in known_cgroups:
            continue # we already printed this one
        if not systemd_name.endswith('.service'):
            continue # this isn't actually a service
        known_cgroups.add(systemd_name)
        print(systemd_name)

if __name__ == '__main__':
    log_running_services()