I want to display a score coming from my database through a json dataset (from the table "score"), which works fine, but my quiz_id is the foreign key, which means the dataset will contain the id, and not the name of the quiz. Which doesn't look good on the CanvasJS graph. The quiz_name is located in the quiz table, with the primary key quiz_id. How would i make the json dataset include the quiz_name instead of quiz_id?
my test.php, which is creating the json:
<?php
header('Content-Type: application/json');
$con = mysqli_connect("123.123.123.123", "Seba0702", "", "kayeetdb");
$data_points = array();
$result = mysqli_query($con, "SELECT * FROM score");
while($row = mysqli_fetch_array($result))
{
$point = array("label" => $row['quiz_id'] , "y" => $row['quiz_score']);
array_push($data_points, $point);
}
echo json_encode($data_points, JSON_NUMERIC_CHECK);
mysqli_close($con);
?>
My tables: Quiz Table:
Score Table:
I want the json to include the quiz_name and quiz_score.
For retrieve infor from another table you need a join
SELECT score.quiz_id, score.student_id, score.quiz_score, quiz.name
FROM score
INNER JOIN quiz on quiz.quiz_id = score.quiz_id
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.