i have a Java Object List
List<MyObject> list = new ArrayList<>();
list.add(new MyObject("1", "1"));
list.add(new MyObject("2", "2"));
list.add(new MyObject("3", "3"));
list.add(new MyObject("4", "12"));
list.add(new MyObject("5", "1d2"));
My Objects Are
Public MyObject {
String id;
String myNumber;
...
}
now i want to sort my list by myNumber by only numbers so i want a result:
MyObject("5", "1d3");
MyObject("4", "12");
MyObject("3", "3");
MyObject("2", "2");
MyObject("1", "1");
How can i do this?
with list.sort(Comparator.comparing(MyObject::getMyNumber)); gives me
MyObject("3", "3");
MyObject("2", "2");
MyObject("5", "1d3");
MyObject("4", "12");
MyObject("1", "1");
I would suggest you write your own compare method inside your object while implementing "Comparable"
something like
public class CompareObject implements Comparable{
String id;
String myNumber;
public CompareObject(String id, String myNumber) {
this.id = id;
this.myNumber = myNumber;
}
public int compareTo(CompareObject c) {
String myNumberOnlyNumbers = "";
String otherNumberOnlyNumbers = "";
for(int i = 0; i < myNumber.length(); i++) {
try {
myNumberOnlyNumbers += Integer.parseInt(myNumber.charAt(i)+"") + "";
} catch (NumberFormatException e) {
}
}
for(int i = 0; i < c.myNumber.length(); i++) {
try {
otherNumberOnlyNumbers += Integer.parseInt(c.myNumber.charAt(i)+"") + "";
} catch (NumberFormatException e) {
}
}
return Integer.compare(Integer.parseInt(myNumberOnlyNumbers), Integer.parseInt(otherNumberOnlyNumbers));
}
}
in your case "CompareObject" would be "MyObject"
after that you can do
List<CompareObject> list = new ArrayList<>();
list.add(new CompareObject("1", "1"));
list.add(new CompareObject("2", "2"));
list.add(new CompareObject("3", "3"));
list.add(new CompareObject("4", "12"));
list.add(new CompareObject("5", "1d3"));
Collections.sort(list, Collections.reverseOrder()); //Collections.reverseOrder() meaning in descending order here
and if i do
for(int i = 0; i < list.size(); i++) {
System.out.println(list.get(i).id + " - " + list.get(i).myNumber);
}
to print the list i get
5 - 1d3
4 - 12
3 - 3
2 - 2
1 - 1
AFAIK there is no java in built solution, but among java developers this is famous as AlphaNumeric sorting and you can find some sample code here.
https://github.com/my-flow/alphanum/blob/master/src/AlphanumComparator.java
Collections.sort(list, new Comparator<MyObject>() {
@Override
public int compare(MyObject o1, MyObject o2) {
String one = o1.myNumber;
String two = o2.myNumber;
if (isNumeric(one) && isNumeric(two)) {
return Integer.valueOf(two).compareTo(Integer.valueOf(one));
} else {
return two.compareTo(one); //add new fuction here to compare strings having alphabets
}
}
});
for(int i=0; i<list.size(); i++){
System.out.println(list.get(i));
}
isNumeric method:
public static boolean isNumeric(String str) {
try {
Double.parseDouble(str);
return true;
} catch(NumberFormatException e){
return false;
}
}
list.sort(Comparator.comparingLong(myobj ->
Long.parseLong(myobj.getMyNumber().replaceAll("\\D", "")
.replaceFirst("^$", "0"))
.reversed());
This assumes you want:
(That is what I read from your example: 13, 12, 3, 2, 1.)
The easiest is to provide a long/int function that derives a long from a MyObject.
(The replaceFirst
ensures that as value without any digit will yield 0.)
List<MyObject> list = new ArrayList<>();
list.add(new MyObject("1", "1"));
list.add(new MyObject("2", "2"));
list.add(new MyObject("3", "3"));
list.add(new MyObject("4", "12"));
list.add(new MyObject("5", "1d2"));
Collections.sort(list, new Comparator<MyObject>() {
@Override
public int compare(MyObject o1, MyObject o2) {
if(Integer.parseInt(o1.getId())<=Integer.parseInt(o2.getId()))
{
return 1;
}else
return -1;
}
});
for(int i=0;i<list.size();i++)
{
System.out.println(list.get(i));
}
I think you problem behind your question shall be 'how to extract numbers from a string', which is well answered in this case. Extract digits from a string in Java
myNumber= myNumber.replaceAll("\\D+","");
And you can create you own comparator to handle the result easily.
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