How to parse xml tags with multiple xmlns attribute?
Question
I have a xml value. I Am try to parse this, but result is null My Xml
<DataPDU xmlns="urn:cma:stp:xsd:stp.1.0">
<Body>
<AppHdr xmlns="urn:iso:std:iso:20022:tech:xsd:head.001.001.01">
<Fr>
<FIId>
<FinInstnId>
<ClrSysMmbId>
<MmbId>4588745121</MmbId>
</ClrSysMmbId>
</FinInstnId>
</FIId>
</Fr>
<To>
<FIId>
<FinInstnId>
<ClrSysMmbId>
<MmbId>3501548751245701797</MmbId>
</ClrSysMmbId>
</FinInstnId>
</FIId>
</To>
<BizMsgIdr>Pac.Convert</BizMsgIdr>
<MsgDefIdr>Pac.Convert.2019</MsgDefIdr>
<BizSvc>Line</BizSvc>
<CreDt>2019-06-07T17:06:35.38Z</CreDt>
</AppHdr>
</Body>
</DataPDU>
My query to parse work good without attribute but with attribute returned null My query:
Select
x.XmlCol.value(N'(./Fr/FIId/FinInstnId/ClrSysMmbId/MmbId)[1]','nvarchar(200)') as FR_MmbId, --Идентификация устанавливается со стороны отправителя
x.XmlCol.value(N'(./To/FIId/FinInstnId/ClrSysMmbId/MmbId)[1]','nvarchar(200)') as TO_MmbId,
x.XmlCol.value(N'(./BizMsgIdr)[1]','nvarchar(200)') as BizMsgIdr
from @Xml.nodes(N'/DataPDU/Body/AppHdr') x(XmlCol)
2 answers
solution1
2 2019-06-12 07:45:26
There are two namespaces involved. Both are without a prefix, hence showing up as the default namespace . All values are living within the inner default namespace . Therefore, to keep it simple, I suggest to use a prefix for the outer. This allows you to address all inner elements without a prefix:
;WITH XMLNAMESPACES(DEFAULT 'urn:iso:std:iso:20022:tech:xsd:head.001.001.01'
,'urn:cma:stp:xsd:stp.1.0' AS ns)
SELECT AppHdr.value(N'(Fr/FIId/FinInstnId/ClrSysMmbId/MmbId/text())[1]','nvarchar(200)') as FR_MmbId
,AppHdr.value(N'(To/FIId/FinInstnId/ClrSysMmbId/MmbId/text())[1]','nvarchar(200)') as TO_MmbId
,AppHdr.value(N'(BizMsgIdr/text())[1]','nvarchar(200)') as BizMsgIdr
FROM @Xml.nodes(N'/ns:DataPDU/ns:Body/AppHdr') A(AppHdr);
Furthermore, you might omit the outer namespace and use wildcard:
;WITH XMLNAMESPACES(DEFAULT 'urn:iso:std:iso:20022:tech:xsd:head.001.001.01')
SELECT AppHdr.value(N'(Fr/FIId/FinInstnId/ClrSysMmbId/MmbId/text())[1]','nvarchar(200)') as FR_MmbId
,AppHdr.value(N'(To/FIId/FinInstnId/ClrSysMmbId/MmbId/text())[1]','nvarchar(200)') as TO_MmbId
,AppHdr.value(N'(BizMsgIdr/text())[1]','nvarchar(200)') as BizMsgIdr
FROM @Xml.nodes(N'/*:DataPDU/*:Body/AppHdr') A(AppHdr);
And the deep search with a doubled slash at the beginning would work too (as long as there is only one <AppHdr> element in your XML.
;WITH XMLNAMESPACES(DEFAULT 'urn:iso:std:iso:20022:tech:xsd:head.001.001.01')
SELECT AppHdr.value(N'(Fr/FIId/FinInstnId/ClrSysMmbId/MmbId/text())[1]','nvarchar(200)') as FR_MmbId
,AppHdr.value(N'(To/FIId/FinInstnId/ClrSysMmbId/MmbId/text())[1]','nvarchar(200)') as TO_MmbId
,AppHdr.value(N'(BizMsgIdr/text())[1]','nvarchar(200)') as BizMsgIdr
FROM @Xml.nodes(N'//AppHdr') A(AppHdr);
Just for fun: This works too (with the given XML, this is not recommended ) :
SELECT @xml.value(N'(//*:Fr//*:MmbId/text())[1]','nvarchar(200)') as FR_MmbId
,@xml.value(N'(//*:To//*:MmbId/text())[1]','nvarchar(200)') as TO_MmbId
,@xml.value(N'(//*:BizMsgIdr/text())[1]','nvarchar(200)') as BizMsgIdr
And even this works (with the given XML, this is not recommended ) :-)
SELECT @xml.value(N'(//*:Fr)[1]','nvarchar(200)') as FR_MmbId
,@xml.value(N'(//*:To)[1]','nvarchar(200)') as TO_MmbId
,@xml.value(N'(//*:BizMsgIdr)[1]','nvarchar(200)') as BizMsgIdr
The general advise is: Be as specific as possible. This helps to avoid name clashes and is better in performance.
solution2
1 2019-06-12 07:11:42
You need to handle XMLNAMESPACES (xmlns) in different nodes to get your desired output. Try as below-
;WITH XMLNAMESPACES(
'urn:cma:stp:xsd:stp.1.0' AS N1,
'urn:iso:std:iso:20022:tech:xsd:head.001.001.01' AS N2,
DEFAULT 'urn:cma:stp:xsd:stp.1.0'
)
Select
x.XmlCol.value(N'(./N2:Fr/N2:FIId/N2:FinInstnId/N2:ClrSysMmbId/N2:MmbId)[1]','nvarchar(200)') as FR_MmbId, --Идентификация устанавливается со стороны отправителя
x.XmlCol.value(N'(./N2:To/N2:FIId/N2:FinInstnId/N2:ClrSysMmbId/N2:MmbId)[1]','nvarchar(200)') as TO_MmbId,
x.XmlCol.value(N'(./N2:BizMsgIdr)[1]','nvarchar(200)') as BizMsgIdr
from @Xml.nodes(N'/N1:DataPDU/Body/N2:AppHdr') x(XmlCol)
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