how to differentiate between different inputs in the same html form using php
Question
I'm building a chatbot in php I want the functionality of that chatbot to be that it is used for resetting the password, so it asks for employee's PIS_CODE which it uses as a primary key to change the password in the password column, you can see my database table.
see it has columns PIS_CODE and password, so I ask the user for PIS_CODE and then it asks the user for the new password and then it changes the password in the corresponding column
so I've been able to take the PIS_CODE and use it as a primary key to reset the password but the password which is reset is the PIS_CODE itself
see here I wanted to reset the password for 41000000 PIS_CODE but it reset the password to 41000000 itself. So it seems like my chatbot assumes the input value to be the pis code and it updates the password column with that value only, so my chatbot is not able to differentiate between different inputs. Plus I want to use only a single form and a single input field. you can see my chatbot here.
HTML Code :
<div class="form-group">
<form action="process.php" id="form" name="f2" method="POST" >
<input type="textarea" id="tt" name="input" placeholder="Type Your Message" style="position:absolute; bottom:0; height:30px; width:100%; height:50px;" required />
</div>
// this is the code which takes the input for the PIS_CODE
$msgg=$_POST['input'];
// this is the code which takes the input for the password
$pass=$_POST['input'];
// the problem is it saves the same input(that is PIS_CODE) in both the variables($msgg and $pass)
FULL Code:
<?php
require_once("config.php");
$msgg=$_POST['input'];
$msg=strtolower($msgg);
$ID = $msg;
$length=strlen($msg);
$flag=0;
$pass=$_POST['input'];
$update = "UPDATE lala SET password='$pass' WHERE PIS_CODE=".$msg;
$res_4=mysqli_query($con,$update);
$sql1 = "SELECT * FROM lala WHERE PIS_CODE='$msg'";
$res_u = mysqli_query($con, $sql1);
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<style>
.in
{
background-color:rgb(64,128,255);
color:white;
padding:10px;
right:0;
width:130px;
text-align: center;
height:auto;
border-radius: 5px;
margin-left: 120px;
margin-bottom: 5px;
}
.out
{
background-color:rgb(241,240,240);
color:black;
padding:10px;
left:5;
width:130px;
text-align: center;
height:auto;
border-radius: 15px;
}
</style>
<body>
<div class="in">
<?php echo "$msgg"; ?>
</div><br>
<div class="out">
<?php
if (($_POST['input']) =='password reset')
{
echo "Do you want to reset your password? ";
}
else if (($_POST['input']) =='yes')
{
echo "Sure, Please provide PIS code ";
}
if (mysqli_num_rows($res_u) == 1)
{
echo 'Pis verified';
echo "Enter new password";
}
if($update){//if the update worked
echo "Update successful!";
}
?>
</div><br>
</body>
</html>
1 answers
solution1
0 ACCPTED 2019-07-08 06:21:22
You could use PHP session. This would do what you want:
require_once("config.php");
$msgg=$_POST['input'];
$msg=strtolower($msgg);
$ID = $msg;
$length=strlen($msg);
$flag=0;
session_start();
if(isset($_SESSION['PIS_CODE'])){
$pass=$_POST['input'];
$update = "UPDATE lala SET password='$pass' WHERE PIS_CODE=".$_SESSION['PIS_CODE'];
$res_4=mysqli_query($con,$update);
unset($_SESSION['PIS_CODE']);
}
else{
$sql1 = "SELECT * FROM lala WHERE PIS_CODE='$msg'";
$res_u = mysqli_query($con, $sql1);
if (mysqli_num_rows($res_u) == 1) {
$_SESSION['PIS_CODE'] = $msg;
}
}
If i were you (ie working on a chatbot), i'd use the $_SESSION object for more than that. You could keep your simple 1 input form, and use PHP session to keep information about the next expected answer, or for a serie of questions like in your example, to know what is the current question, an many other possible usage.
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