In some cases the key which is returned by array_search() is 0 or 1. When I use this return value in an if-statement, php interprets it as boolean.. but I want it to be interpreted as a string. How can i do this?
example:
$array=array('abc','a','b');
$returnvalue=array_search('abc',$array); // will be 0
if($returnvalue!=false){
statement // right now, this will not be executed
}
thanks a lot for your help!
Use type safe comparisons:
if ($returnvalue !== false)
The same is also supported for ==, with ===:
if ($returnvalue === false)
{
// not found
}
==
compare for value
===
compare for value and data type
See:
$array = array('abc','a','b');
$returnvalue = array_search('abc', $array); // will be 0
if($returnvalue == false){
// Executed
var_dump($returnvalue);
}
if($returnvalue === false){
// Not executed
var_dump($returnvalue);
}
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