How to display user input after prompt in python?

Question

I'm currently coding a text based game in python in which the narrative will start differently depending on answers to certain questions. The first question is simple, a name. I can't seem to get the input to display in the correct text option after the prompt.

I tried using

"if name is True"

and

"if name is str"

but they both skip to the else option, instead of displaying the correct option after input.

while True:
    try:
        # This will query for first user input, Name.

        name = str(input("Please enter your name: "))
    except ValueError:
        print("Sorry, I didn't understand that.")

        # No valid input will restart loop.

        continue
    else:

        break

if name is str:
    print("Ah, so " + name + " is your name? Excellent.")
else:
    print("No name? That's fine, I suppose.")

So if I enter John as my name, I'd expect the output to be "Ah, so John is your name? Excellent."

But instead I enter John and it outputs:

Please enter your name: John

No name? That's fine, I suppose.

Any help would be appreciated. Thanks.

Answer 1

The exception handling around input is not required as the input function always returns a string. If the user does not enter a value an empty string is returned.

Therefore your code can be simplified to

name = input("Please enter your name: ")

# In python an empty string is considered `False` allowing 
# you to use an if statement like this.
if name:
    print("Ah, so " + name + " is your name? Excellent.")
else:
    print("No name? That's fine, I suppose.")

Further regarding usage of is :

is is used to compare identity as in two variables refer to the same object. It's more common use is to test if a variable is None eg if name is None ( None is always the same object). As mentioned you can use type(name) to obtain the type of variable name but this is discouraged in place of the builtin check isinstance .

== on the other hand compares equality as in if name == "Dave" .

isinstance does more than just check for a specific type, it also handles inherited types.

Answer 2

问题是您要检查name是否为str，而不是type（name）是否为str。

  if type(name) is str:

Answer 3

use isinstance instead of is . And, You do not need to use str(input()) because input returns str .

while True:
    try:
        # This will query for first user input, Name.
        name = input("Please enter your name: ")
    except ValueError:
        print("Sorry, I didn't understand that.")
        # No valid input will restart loop.
        continue
    else:
        break

if isinstance(name, str):
    print("Ah, so " + name + " is your name? Excellent.")
else:
    print("No name? That's fine, I suppose.")

The result is:

Please enter your name: John
Ah, so John is your name? Excellent.

But, You have to use string.isalpha() if you want to check whether name is real name in consist of alphabets.

if name.isalpha():
    print("Ah, so " + name + " is your name? Excellent.")
else:
    print("No name? That's fine, I suppose.")