Coming to catch if a statement in try gives error

Question

I am using async await , from one function to another with try catch statements for catching errors. Here function1 and function2 are on different files:

function1 = async (req, res) => {
    try {
        const foo = await function2(req.body.name);
        res.status(200).send(foo);
    } catch (e) {
        res.status(500).send(e);
    }
}


function2 = async (name) => {
    try {
        const result = await db.find({name: name});
        if (result) return result;
    } catch (e) {
        return e;
    }
}

If the error comes in the db.find it goes to catch statement of function2 . How to make sure that if it comes to catch statement of function2 then the return goes to catch statement of function1

Answer 1

Use throw to send error to upper level functions, in your case you can do

function2 = async (name) => {
    try {
        const result = await db.find({name: name});
        if (result) return result;
    } catch (e) {
      // do some logging if needed, like
        console.log(e);
        throw e;
    }
}

also if you are not doing any logging or error handling in function2 you should not use try catch, it will directly handled by function1

function2 = async (name) => {
         const result = await db.find({name: name});
        if (result) return result;
}

Answer 2

Just use throw e here is snippet

 // test wrapper let db = { find: (x) => new Promise((res,rej)=>setTimeout(x=>rej('NO DATA'),1000)) } function1 = async (req, res) => { try { console.log('Find...'); const foo = await function2('abc'); console.log('func1'); } catch (e) { console.log('outer err', e); } } function2 = async (name) => { try { const result = await db.find({name: name}); console.log('func2'); } catch (e) { console.log('inner err', e); throw e; } } function1(0,0);