how to select the last characters of a file name in python

Question

Is there any efficient way to select the last characters of a string file Name until there's a Slash / in Python?

For example, I got the following file Name:

File=r"C:\Users\folder1\folder2\folder3/fileIwanttoget.txt"

I would like to select only the string:

string=fileIwanttoget.txt

Independently of the number of characters that this file name has.

Answer 1

pathlib is a modern approach to path handling and makes these tasks easy:

from pathlib import Path

f = Path("C:\Users\folder1\folder2\folder3/fileIwanttoget.txt")
f.name

fileIwanttoget.txt

Also, when you have a Path object you can open it directly:

from pathlib import Path

f = Path("C:\Users\folder1\folder2\folder3/fileIwanttoget.txt")
with f.open('r', encoding='utf8') as file_in:
    process(file_in)

Answer 2

You should use the python libraries that deal with file paths. The os.path is a good place to look into it.

from os.path import basename
string=basename(File)

Answer 3

If you simply want to split your string, you could do:

file_name = r"C:\Users\folder1\folder2\folder3/fileIwanttoget.txt"

ending = file_name.split('/')[-1]
print(ending)
# fileIwanttoget.txt

See the documentation on .split() . If you prefer working directly with paths, you should consider monkuts answer.