I have the following list:
lst <- list(a = "", b = 2)
and want to deparse it to text:
> deparse(lst, width.cutoff = 100)
[1] "structure(list(a = \"\", b = \"\"), .Names = c(\"a\", \"b\"))"
and then i want to run the text as code (in the console):
> structure(list(a = \"\", b = \"\"), .Names = c(\"a\", \"b\"))
Error: unexpected input in "structure(list(a = \"
I know it Fails, because of the backslashes: (without them it works obviously).
structure(list(a = "", b = ""), .Names = c("a", "b"))
Question:
How can i avoid creating the backslashes?
What i tried:
I went through the given Parameter. Backtick seemed like a candidate, but didnt work. Using gsub to replace them is a candidate, but way to dirty i guess,..
Tools:
R 3.4.3 Rstudio 1.1.447
Update: Upgrade to 3.6 - similar issue.
> lst <- list(a = "", b = 2)
> deparse(lst, width.cutoff = 100)
[1] "list(a = \"\", b = 2)"
> list(a = \"\", b = 2)
Error: unexpected input in "list(a = \"
There are couple of ways to modify the behavior. One way is to print with cat
on the console, copy and paste that (used R 3.6.0
)
out <- deparse(lst, width.cutoff = 100)
cat(out, sep="\n")
#list(a = "", b = 2)
list(a = "", b = 2)
#$a
#[1] ""
#$b
#[1] 2
Note that cat
also have a file
argument if the output needs to be written to some file and used it later
Or use gsub
to remove the "
and replace with single quotes ( '
)
out1 <- gsub('"', "'", out)
out1
#[1] "list(a = '', b = 2)"
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