Object value by key return undefined

Question

I have object like the one below and every time i call object["key"] it return undefined for some reason

i tried the following and still getting undefined

object.keyName

object[keyName]

object["keyName"]

all of them return undefined

let sam = {
  "facebook": "https://facebook.com",
  "instagram": "https://Instagram.com",
  "placeName": "dazzlement",
  "snapchat": "https://snapchat.com",
  "twitter": "https://twitter.com",
}

let's say i want placeName value i tried

sam.placeName
sam[placeName]
sam["placeName"]

all of them return undefined.

-------- UPDATE ----------

i'm using react native with Parse JS SDK here is the code for getting values from Parse Database and send it as props to a component where it will display the results as card

this.state = {
    items: null,
    loaded: false
};



componentDidMount() {
    this.queryValues()
}

queryValues = async id => {

    let cy = this;
    const GameScore = Parse.Object.extend('social');
    const query = new Parse.Query(GameScore);
    query.equalTo('A', 1);
    query.equalTo('B', 2);
    const results = await query.find().then(
        results => {
            cy.setState({
                items: results
                loaded: true,
            })
        },
        error => {}
    );

};

render() {
            return (

                {
                    this.state.loaded ?
                    <FlatList
                    data = {this.state.items}
                    renderItem = {
                        ({item}) => <SocialCard social={item} /> } /
                        >
                        : <
Text> Loading </Text>
}


                    );
                }
            }

In the component here is the code

render() {
    const {
      social
    } = this.props;
    console.log(social)
    return (
      <Text>{this.props.}</Text>

    );
  }

the log show up like this

Object { 
"facebook": "https://facebook.com", 
"instagram": "https://Instagram.com", 
"placeName": "dazzlement", 
"snapchat": "https://snapchat.com", 
"twitter": "https://twitter.com", 
}

Answer 1

this should return all links

let sam = {
    facebook: 'facebook.com', // you don't need " " for facebook
    instagram: 'instagram.com'
}

for (let i in sam){
    console.log(sam[i])
}

sam.facebook // facebook.com
sam.instagram // instagram.com