I'm trying to make a basic pig latin translator but the editor keeps showing me a syntax error.
ay = "ay"
way = "way"
consonants = ("b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "n", "p", "q", "r", "s", "t", "v", "w", "x", "y", "z")
vowels = ("a", "e", "i", "o", "u")
user_word = input("Enter your word here: ")
first_letter = user_word[0]
first_letter = str(first_letter)
first_letter = first_letter.upper()
if first_letter in consonants:
print(first_letter + "is a consonant.")
remove_first_letter = user_word[1:]
pig_latin = remove_first_letter + first_letter + ay
print("The word in Pig Latin is " + pig_latin)
elif first_letter in vowels:
print(first_letter + "is a vowel.")
pig_latin = user_word + way
print("The word in Pig Latin is " + pig_latin)
else:
print("I don\'t know what" + first_letter + "is.")
This is what i have come up with. The exact error message that it shows is:
File "<ipython-input-33-8e1536233f19>", line 14
elif first_letter in vowels:
^
SyntaxError: invalid syntax
Python is an indentation-dependent language. elif
and else
need to be at the same depth as if
, and whatever statement depends on the condition needs to be indented further.
For example:
if first_letter in consonants:
print(first_letter + "is a consonant.")
remove_first_letter = user_word[1:]
pig_latin = remove_first_letter + first_letter + ay
print("The word in Pig Latin is " + pig_latin)
elif first_letter in vowels:
print(first_letter + "is a vowel.")
pig_latin = user_word + way
print("The word in Pig Latin is " + pig_latin)
else:
print("I don\'t know what" + first_letter + "is.")
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