How can i handle this exception
This is for catch error from JPA persistence
try {
if (platform.getPlatformId() == null) {
messageString = "inserted";
} else {
messageString = "updated";
}
Platform platf = platformServiceImpl.addOne(platform);
model.addAttribute("locations", locationServiceImpl.getAll());
//Date localDate = new Date();
//PlatformDetail newDetailPlatform = new PlatformDetail();
//newDetailPlatform.setLastUpdate(localDate);
//newDetailPlatform.setPlatform(platform);
//platformDetailServiceImpl.addOne(newDetailPlatform);
//redirectAttributes.addAttribute("platformId", platf.getPlatformId());
redirectAttributes.addFlashAttribute("success", messageString);
return "redirect:/admin/step1/" + platf.getPlatformId();
} catch (PersistenceException ex) {
redirectAttributes.addFlashAttribute("error", "dfdf");
return "redirect:/admin/step1/" + ex.getCause();
}
I expected send a RedirectParameter with the key duplicate and show as a message
In the catch
section, redirect just to /admin/step1
or some other endpoint with a message that something went wrong. Adding ex.getCause()
makes no sense, because getCause()
returns a Throwable
object (to be precise: object implementing Throwable
interface).
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