how to find minimum score of a 2d array?

Question

How to find minimum score of a 2d array .

---

My array is like :

[['john', 20], ['jack', 10], ['tom', 15]]

I want find the minimum score of student and print his name. tell me how to write that?

Answer 1

If you want to get only one student:

student_details = [['john', 20], ['jack', 10], ['tom', 15]]
student_detail_with_min_score = min(student_details, key=lambda detail: detail[1])
print(student_detail_with_min_score)
print(student_detail_with_min_score[0])
print(student_detail_with_min_score[1])

Output:

['jack', 10]
jack
10

min function finds the minimum of student_details , but it will use student_details[i][1] as the key while comparing.

Read the official documentation to understand how the min function works with the key argument.

---

If you want to get all the students with the minimum score:

student_details = [['rock', 10], ['john', 20], ['jack', 10], ['tom', 15]]

min_score = min(student_details, key=lambda detail: detail[1])[1]

student_details_with_min_score = [
    student_detail for student_detail in student_details if student_detail[1] == min_score
]

print(student_details_with_min_score)

Output:

[['rock', 10], ['jack', 10]]