i am trying to implement a webview that start a video intent, and return the video to a webView.
What i try to do:
1) Java - add webAppInterface that open video capture intent:
mWebView = (WebView) findViewById(R.id.webView);
mWebView.addJavascriptInterface(webAppInterface, "Android");
public class WebAppInterface {
...
public void dispatchTakeVideoIntent() {
Intent takeVideoIntent = new Intent(MediaStore.ACTION_VIDEO_CAPTURE);
takeVideoIntent.putExtra(android.provider.MediaStore.EXTRA_DURATION_LIMIT,10);
if (takePictureIntent.resolveActivity(mContext.getPackageManager()) != null) {
((AppCompatActivity) mContext).startActivityForResult(takeVideoIntent, REQUEST_VIDEO_CAPTURE);
}
}
...
2) JavaScript - Call it from the webview:
Android.dispatchTakeVideoIntent()
3) Java - Get the Uri, and send path to my webview
public void onActivityResult(int requestCode, int resultCode, Intent intent) {
if (requestCode == REQUEST_VIDEO_CAPTURE && resultCode == Activity.RESULT_OK) {
Uri videoUri = intent.getData();
wView.loadUrl("javascript:test('" + videoUri.getPath() + "')");
}
}
4) JavaScript - Get the path in my webView
window.test = (videoUriPath) => {
...
}
My question is, how to access the video?
And maybe there is a totally different way to go about it?
Accessing the video means I'll suppose playing the video in webView. Have a video element in your HTML (suppose id is 'my-video'), then your javascript will be:
window.test = (videoUriPath) => {
var video = document.getElementById('video');
var source = document.createElement('source');
source.setAttribute('src', videoUriPath);
video.appendChild(source);
video.load();
video.play();
}
ok i found a solution, its a little overkill, but its working...
1) JAVA: convert the video to bytes array
byte[] bytes;
byte[] data = new byte[16384];
int bytesRead;
ByteArrayOutputStream output = new ByteArrayOutputStream();
while ((bytesRead = is.read(data)) != -1) {
output.write(data, 0, bytesRead);
}
bytes = output.toByteArray();
2) JAVA: send encoded chunks (base64) to the webvView
int startIndex = 0;
int chunkSize= 16384;
while(startIndex < bytes.length){
byte[] newArray = Arrays.copyOfRange(bytes, startIndex, startIndex + chunkSize);
startIndex = startIndex + chunkSize;
encodedString = Base64.encodeToString(newArray, Base64.DEFAULT);
wView.loadUrl("javascript:g_sendFile_f('" + encodedString + "')");
}
wView.loadUrl("javascript:g_sendFile_f('" + "finish" + "')");
3) JAVASCRIPT: receive the encode chunks, combine them, and create blob file
let bytesArrFinal_an = []
window.g_sendFile_f = (msg) =>{
// last call
if(msg === "finish"){
let blob = new Blob(byteArrFinal_an,{type : "video/mp4"})
this.test_videoUrl = URL.createObjectURL(blob);
console.log("finish")
return
}
// add bytes to final array
let bytesArr_an = this.b64toByteArr(msg)
bytesArrFinal_an = bytesArrFinal_an.concat(bytesArr_an);
console.log(msg)
}
If someone have a more elegant solution i will be happy the see it!
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