I am trying to filter a dataframe in scala by comparing two of its columns (subject and stream in this case) to a list of tuples. If the column values and the tuple values are equal the row is filtered.
val df = Seq(
(0, "Mark", "Maths", "Science"),
(1, "Tyson", "History", "Commerce"),
(2, "Gerald", "Maths", "Science"),
(3, "Katie", "Maths", "Commerce"),
(4, "Linda", "History", "Science")).toDF("id", "name", "subject", "stream")
Sample input:
+---+------+-------+--------+
| id| name|subject| stream|
+---+------+-------+--------+
| 0| Mark| Maths| Science|
| 1| Tyson|History|Commerce|
| 2|Gerald| Maths| Science|
| 3| Katie| Maths|Commerce|
| 4| Linda|History| Science|
+---+------+-------+--------+
List of tuple based on which the above df needs to be filtered
val listOfTuples = List[(String, String)] (
("Maths" , "Science"),
("History" , "Commerce")
)
Expected result:
+---+------+-------+--------+
| id| name|subject| stream|
+---+------+-------+--------+
| 0| Mark| Maths| Science|
| 1| Tyson|History|Commerce|
| 2|Gerald| Maths| Science|
+---+------+-------+--------+
You can either do it with isin
with structs (needs spark 2.2+):
val df_filtered = df
.where(struct($"subject",$"stream").isin(listOfTuples.map(typedLit(_)):_*))
or with leftsemi join:
val df_filtered = df
.join(listOfTuples.toDF("subject","stream"),Seq("subject","stream"),"leftsemi")
You can simply filter
as
val resultDF = df.filter(row => {
List(
("Maths", "Science"),
("History", "Commerce")
).contains(
(row.getAs[String]("subject"), row.getAs[String]("stream")))
})
Hope this helps!
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