How do I append a dictionary as another value to an existing dictionary key

Question

I currently have a nested dictionary, with a dictionary as a value

I want to add another dictionary as SECOND item to the same key so that it looks something like this:

{'mykey1': {'-11111': 0, 'A': 1}, {Second dictionary}, ...}

"append" doesn't work and "update" replaces the value.

Do I need something like a list of dictionaries for the value?

{'mykey1': [{'-11111': 0, 'A': 1}, {'-11111': 201910, 'A': 201910}] ,
 'mykey2': [{'-11111': 0, 'A': 1}, {'-11111': 201909, 'A': 201910}]}

In which case: a) How do I append the second dictionary element to each key in the existing dict? b) How do I access that second dictionary? thanks

Answer 1

Yes you need a list or a tuple for your Task. try to store the two dictionaries in a list and then assign it to the wrapper dictionary

ls = [{'-11111': 0, 'A': 1},{'-11111': 201910, 'A': 201910} ]

dic = {}
dic["myKey1"] = ls

or simply:

ls = [{'-11111': 0, 'A': 1},{'-11111': 201910, 'A': 201910} ]

dic = {"mykey": ls}
print(dic)  # {'mykey': [{'-11111': 0, 'A': 1}, {'-11111': 201910, 'A': 201910}]} 

Answer 2

you just need to build each object in turn.

first_dict{key}.update(list(first_dict{key}, {second_dict}.

will take the existing value from the dictionary for a given key and replace it with a list of that value plus another dictionary, second_dict

It isn't totally clear to me what how you want to structure your data.

If you built a little example of exactly what you want the data to be structured as, it'll be easier to give an exact answer.