I have a string that is in the format of k1=v1,k2=v2
and so on. I want to return that k
which has highest v
.
I am trying to run below code but it does not seem to work -
s1 = "0=0.0,1=4.097520999795124e-05,2=0.0007278731184387373,3=0.339028551210803,4=0.33231086508575525,5=0.32789173537500504"
stats = dict(map(lambda x: x.split('='), s1.split(',')))
x = max(stats, key=stats.get)
print(x)
This prints 1
whereas the expected output is 3
.
You could use max
, with a key to consider only the second value in the key
/ value
tuples. Also note that the values
must be cast to float
, since otherwise element's comparisson will be lexicographical:
from operator import itemgetter
max_val = max(((k,float(v)) for k,v in stats.items()), key=itemgetter(1))
print(max_val)
# ('3', 0.339028551210803)
print(max_val[0])
# 3
First, convert your string dictionary to one keyed on integers with floats as the values.
s1 = "0=0.0,1=4.097520999795124e-05,2=0.0007278731184387373,3=0.339028551210803,4=0.33231086508575525,5=0.32789173537500504"
d = dict(pair.split('=') for pair in s1.split(','))
d = dict(zip([int(k) for k in d], [float(v) for v in d.values()]))
>>> d
{0: 0.0,
1: 4.097520999795124e-05,
2: 0.0007278731184387373,
3: 0.339028551210803,
4: 0.33231086508575525,
5: 0.32789173537500504}
Then use itemgetter
per the related question to get the key for the max value in a dictionary.
import operator
>>> max(d.items(), key=operator.itemgetter(1))[0]
3
Your method works as well once the dictionary is in the correct format:
>>> max(d, key=d.get)
3
Your issue is that '4.097520999795124e-05' evaluates higher than '0.339028551210803' when lex sorted.
This seems to work for me:
>>> stats = { "1": "a", "2": "b", "3": "c"}
>>> max([ int(i) for i in stats.keys()])
3
Take stats.keys()
, replace each with a true int with a list comprehension, and then take the max of that list.
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