How to get Python dictionary with the highest key value?

Question

I have a dictionary with latitude and longitude values passed from a different file.

absoluteList = {"latitude": absolute[1], "longitude": absolute[0]}

If we print absoluteList we get:

{'latitude': 507476711, 'longitude': -18299961}
{'latitude': 507447383, 'longitude': -18388366}
{'latitude': 507436793, 'longitude': -18459606}
{'latitude': 507427288, 'longitude': -18500804}
{'latitude': 507410993, 'longitude': -18521404}
{'latitude': 507395241, 'longitude': -18552732}
{'latitude': 507362921, 'longitude': -18550157}
{'latitude': 507344995, 'longitude': -18521404}

I need to print out the dictionary with the highest latitude value.

Answer 1

Just use max :

absoluteList = [
{'latitude': 507476711, 'longitude': -18299961},
{'latitude': 507447383, 'longitude': -18388366},
{'latitude': 507436793, 'longitude': -18459606},
{'latitude': 507427288, 'longitude': -18500804},
{'latitude': 507410993, 'longitude': -18521404},
{'latitude': 507395241, 'longitude': -18552732},
{'latitude': 507362921, 'longitude': -18550157},
{'latitude': 507344995, 'longitude': -18521404}
]

biggest_latitude = max(absoluteList, key=lambda x: x['latitude'])

{'latitude': 507476711, 'longitude': -18299961}

Answer 2

print( max(absoluteList, key=lambda x: x['latitude']))

Answer 3

The are 2 ways to do it is by

1. using itemgetter()

    from operator import itemgetter highest_value_in_list = max(absoluteList, key=itemgetter('latitude'))`

2. using max :

   highest_value_in_list = max(absoluteList, key=lambda x: x['latitude'])

output:

{'latitude': 507476711, 'longitude': -18299961}