I've been tasked with creating a "pown-chess" game, and i'm trying to figure out how to code the win condition. Is there any way to have python count the number of times a given value appears in a dictionary?
You can make a list of the dict's values, and use its count
method.
result = list(mydict.values()).count(value)
The simplest way for a beginner (like me) is to apply Counter from collections to the values of your dictionary:
from collections import Counter
d=dict([(2,1),(3,1),(4,2),(5,1),(6,3),(7,2),(8,3)])
# d:(key,val) --> dd:(val,freq_of_val_in_d)
dd=Counter(d.values())
print(dd)
gives:
Counter({1: 3, 2: 2, 3: 2})
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