I need to write an 8 ball code that has eleven options to display and it needs to pull from a text file. I have it taking lines from the text file but sometimes it takes an empty line with no writing. And I need it to only take a line that has writing. Here are that options it needs to draw from: Yes, of course, Without a doubt. yes. You can count on it. For sure.Ask me later. I'm not sure. I can't tell you right now. I'll tell you after my nap, No way.I don't think so. Without a doubt, no. The answer is clearly NO.
string line;
int random = 0;
int numOfLines = 0;
ifstream File("file.txt");
srand(time(0));
random = rand() % 50;
while (getline(File, line))
{
++numOfLines;
if (numOfLines == random)
{
cout << line;
}
}
}
IMHO, you need to either make the text lines all the same length, or use a database (table) of file positions.
Minimally, create a std::vector<pos_type>
.
Next read the lines from the file, recording the file position of the beginning of the string:
std::vector<std::pos_type> text_line_positions;
std::string text;
std::pos_type file_position = 0;
while (std::getline(text_file, text)
{
text_line_positions.push_back(file_position);
// Read the start position of the next line.
file_position = text_file.tellg();
}
To read a line from a file, get the file position from the database, then seek to it.
std::string text_line;
std::pos_type file_position = text_line_positions[5];
text_file.seekg(file_position);
std::getline(text_file, text_line);
The expression, text_line_positions.size()
will return the number of text lines in the file.
If the file fits in memory, you could use std::vector<string>
:
std::string text_line;
std::vector<string> database;
while (getline(text_file, text_line))
{
database.push_back(text_line);
}
To print the 10 line from the file:
std::cout << "Line 10 from file: " << database[9] << std::endl;
The above techniques minimize the amount of reading from the file.
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