I am trying (emphasis on trying:P) solve an exercise where i need to merge two sorted linked list, whereby the element of the first list comes first.
My input is:
[1,2,4] [1,3,4]
My expected output would be:[1,1,2,3,4,4]
The output, which I am actually getting is: [1,1,3,4]
So it looks like, that I m messing something up with the pointers. I merge the first elements of both lists and then just append the second list instead of continuing merging. I m sure its a pretty easy fix, but I am not getting it... :(
Here is my spaghetti code:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
// if one of the lists is null, then return the other one
if(l1 == null){
return l2;
}
if(l2 == null){
return l1;
}
// create a new list and add the first two elements two it
ListNode result = l1;
result.next = l2;
// introduce a running pointer
ListNode current = result;
current = current.next;
l1 = l1.next;
l2 = l2.next;
// Here i assume that the lists have the same length for now
while(l1 != null && l2 != null){
current.next = l1;
current.next.next = l2;
current = current.next;
l1 = l1.next;
l2 = l2.next;
}
return result;
}
}
Your algo for the said problem is wrong
I can see your concepts about pass by value
and pass by reference
are not clear
I would suggest you to google the above phrases
and for your problem refer to https://www.geeksforgeeks.org/merge-two-sorted-linked-lists/
this is not exactly related to your problem but you should be able to figure your way around.
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