this is my array in js:
const array = [
{
id: 1,
userId: 1,
title: 'test1',
},
{
id: 2,
userId: 1,
title: 'test2',
},
{
id: 3,
userId: 1,
title: 'test3',
},
{
id: 4,
userId: 1,
title: 'test4',
}
]
and I only need to grab the object where I know its id and assign it to a variable. I know that I will need an object with id number 1 so I would like to:
const item = {
id: 1,
userId: 1,
title: 'test1',
},
Use Array.find :
const array = [ { id: 1, userId: 1, title: "test1" }, { id: 2, userId: 1, title: "test2" }, { id: 3, userId: 1, title: "test3" }, { id: 4, userId: 1, title: "test4" } ]; const item = array.find(({ id }) => id === 1); console.log(item);
Array
has a filter
function on its prototype that allows you to filter the values using a function, which gets passed each value in the array in turn. If the condition you specify in your function returns true, your value is returned.
So in this case:
const myArray = [
{
id: 1,
userId: 1,
title: 'test1',
},
{
id: 2,
userId: 1,
title: 'test2',
},
{
id: 3,
userId: 1,
title: 'test3',
},
{
id: 4,
userId: 1,
title: 'test4',
}
]
const idToFind = 1;
const foundValues = myArray.filter(item => item.id === idToFind)
Then if you knew only one value would you found, you would just take the first item in the foundValues array:
const foundItem = foundValues[0]
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