Python: Create directory structure according to dict

Question

In Python, given a dict (list or sequence) as in:

d={'a': 9, 'b': 6, 'c': 10],

I would like to create, in a clever way, the a directory structure like this:

'a_9/b_6/c_10'.

Answer 1

import os

def make_dir(dictionary):
  for key, val in dictionary.items():
    new_dir = f"{key}_{val}"
    os.mkdir(new_dir)
    os.chdir(new_dir)

EDIT: Or even more concise

import os
os.makedirs("/".join(f"{key}_{val}" for key, val in d.items()))

Answer 2

Dictionaries are not strictly ordered in Python (although as of Python 3.6 there is some level of order ), but if you sorted it (assuming you want that), perhaps by key, you could try something like follows:

new_dir = os.path.join(*[f'{k}_{v}' for k, v in sorted(d.items())])
os.makedirs(new_dir)