How to exit while loop

Question

I don't understand why I cannot go out from simple loop.

Here is the code:

a = 1

#tip checking loop
while a != 0:
    # tip value question - not defined as integer to be able to get empty value
    b = input("Give me the tip quantinty which you gave to Johnnemy 'hundred' Collins :")
    # loop checking if value has been given
    if b:
        #if b is given - checking how much it is
        if int(b) >= 100:
            print("\nJohnny says : SUPER!")
        elif int(b) < 100:
            print("\nJohnny says : Next time I spit in your soup")
    elif b == '0':
        a = 0

    else:
        print("You need to tell how much you tipped")

print("\n\nZERO ? this is the end of this conversation")

Thanks for your help.

Answer 1

This should solve your problem:

a = 1

#tip checking loop
while a != 0:
    # tip value question - not defined as integer to be able to get empty value
    b = input("Give me the tip quantinty which you gave to Johnnemy 'hundred' Collins :")
    # loop checking if value has been given
    if b:
        #if b is given - checking how much it is
        if int(b) >= 100:
            print("\nJohnny says : SUPER!")
        elif int(b) < 100:
            print("\nJohnny says : Next time I spit in your soup")
        if b == '0':
            a = 0

    else:
        print("You need to tell how much you tipped")

print("\n\nZERO ? this is the end of this conversation")

the following condition

if b == '0':
    a = 0

should be in the same scope as the if b: condition.

Answer 2

You can t break out of the loop because. actually, there is no t break out of the loop because. actually, there is no break . You need to put . You need to put break` command at the end of every loop branch where you would like to stop looping in order to break out of the loop.

Also, you could break out assigning a = 0 instead of the break .