I have a string field : "[Paris, Marseille, Pays-Bas]"
. I want to convert this string to a list of strings.
For now I have the following function :
def stringToList(string):
string = string[1:len(string)-1]
try:
if len(string) != 0:
tempList = string.split(", ")
newList = list(map(lambda x: str(x), tempList))
else:
newList = []
except:
newList = [-9999]
return(newList)
I want to know if there is a simpler or a shorter method with the same results. I could use ast.literal_eval()
if my input data were of type int
. But in my case, it does not work.
Thank you
Worth to know:
import re
string = "[Paris, Marseille, Pays-Bas]"
founds = re.findall('[\-A-Za-z]+', string)
It will find all that consist at least one of of -
, AZ
, and az
.
One pros is that it can work with less-neat strings like:
string2 = " [ Paris, Marseille , Pays-Bas ] "
string3 = " [ Paris , Marseille , Pays-Bas ] "
This splits it into a list of strings:
'[Paris, Marseille, Pays-Bas]'.strip('[]').split(', ')
# ['Paris', 'Marseille', 'Pays-Bas']
Just use slicing and str.split
:
>>> s = '[Paris, Marseille, Pays-Bas]'
>>> s[1:-1].split(', ')
['Paris', 'Marseille', 'Pays-Bas']
>>>
Or str.strip
with str.split
:
>>> s = '[Paris, Marseille, Pays-Bas]'
>>> s.strip('[]').split(', ')
['Paris', 'Marseille', 'Pays-Bas']
>>>
try this :
s = "[Paris, Marseille, Pays-Bas]"
s = [i.replace('[','').replace(']','').replace(' ','') for i in
s.split(',')]
print(s)
output:
['Paris', 'Marseille', 'Pays-Bas']
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