long x = <some value>
int y = <some value>
I want to subtract y from x , which of the following will give me different or same results
x = (int)x - y;
x = x-y
x = short(x) - short(y)
The type long
is "bigger" than int
. Smaller types can be automatically casted to bigger types. So, this code:
someLongNumber + someIntNumber
is basically equal to
someLongNumber + (long)someIntNumber
So the output will be long
. You don't have to cast if you want to place the result in x
. However, if you want to place it in y
, you must cast the x
operand to int
( (int)x
), or the whole operation ( (int)(x - y)
).
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