selecting text of a page in selenium webdriver python
Question
I'm a relative beginner in python and selenium and am facing an issue. Using Selenium, I click on a link that by default opens in a new tab and I want to print all the text of the new page in my termianal, How do I accomplish this? please share your code. Attaching a snippet of the page source.
<html><head><script src="chrome-extension://mooikfkahbdckldjjndioackbalphokd/assets/prompt.js"></script></head><body><pre style="word-wrap: break-word; white-space: pre-wrap;">
using namespace std;
int main() {
int n;
cin >> n;
return 0;
}
</pre>
</body>
</html>
I need to print the code enclosed in the 'pre' tag in my terminal.
1 answers
solution1
0 2019-12-21 19:04:34
As you say if your page only contains HTML that you have provided, you can do the following.
from selenium import webdriver
driver= webdriver.Chrome("chromedriverr")
driver.get("your_test_site_url")
print(driver.find_element_by_xpath("/html/body/pre").text)
When you run the program you get following output in terminal.
using namespace std;
int main() {
int n;
cin >> n;
return 0;
}
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