C++ : how do I make the program exactly like in the picture?

Question

*Buatlah program untuk menghitung perkalian deret bilangan genap membentuk segitiga siku terbalik dengan hasil seperti pada gambar di atas.

my program is like this :

#include <stdio.h>
#include <conio.h>
#include <iostream>
#include <iomanip>

using namespace std;

int main(int argc, const char *argv[])
{
    int i, j, n;
    for(i=0; i<5; puts(""),++i)
    {
        n=0;
        for(j=5; j>i; n+=2*(j--))
        {
            if(j>i+1) {
                printf("%d * ",2*j);
            }
            else {
                printf("%d ",2*j);
            }
        }
        printf("\t= %d",n);
    }
    printf("\t\t110");
    return(0);
}

how do I make the program exactly like in the picture above?

Answer 1

This code gives the output you stated in your question. I'm not sure though if you are intended to do it like this, since there might be a smarter solution using iomanip and iostream, because you included it.

#include <stdio.h>

using namespace std;

int main(int argc, const char *argv[])
{
    int i, j, n;
    for(i=0; i<5; puts(""),++i)
    {
        n=0;
        for(j=5; j>i; n+=2*(j--))
        {
            if(j>i+1) {
                printf("%d + ",2*j);
            }
            else {
                printf("%d ",2*j);
            }
        }
        for (int k = 0; k <= i; k++) printf("    ");
        printf("= %d",n);
    }
    printf("\t\t    ---------- +\n");
    printf("\t\t\t 110\n");
    return(0);
}

Answer 2

#include <iostream>
using namespace std;

int main(int argc, const char *argv[]){
    int i,  k, n, s=0;

    for(k=2; k <= 10; k+=2) {
        n=0;
        for(i=10; k <= i; i-=2) {
            if (k < i)
                cout<<i<<" + " ;
            else {
                cout<< i;
                cout.width(k*2);
                cout<< right<< " = ";
            }
            n+=i;
        }
    cout<<n<<"\n";
    s += n;
    }
    cout<< "------------------------- +"<<"\n";
    cout<< "                     "<<s<<"\n";
    return 0;
}