how to sort a dictionary by key first then by tuple values

Question

Given an input dictionary like

{13: (3,1,7), 2: (6,4,9), 7: (5,8,4)}

get an out put dictionary like

{2: (4,6,9), 7: (4,5,8), 13: (1,3,7)}

Answer 1

From Python 3.6 onwards, dictionaries honor insertion order. You can accomplish what you want by using sorted at the level of both the dict items as well as within the individual values:

>>> dict(sorted((k, tuple(sorted(v))) for (k, v) in a.items()))
{2: (4, 6, 9), 7: (4, 5, 8), 13: (1, 3, 7)}

Answer 2

You can use comprehension.

a = {13: (3,1,7), 2: (6,4,9), 7: (5,8,4)}
sorted_a = {key:tuple(sorted(a[key])) for key in sorted(a)}