Get the following Yearmonth

Question

我将如何获得 202001

@year = 2019 and @month = 12

Where [yearmonth] = CONCAT(@Year, @Month) + 1

Answer 1

Where [yearmonth] = FORMAT(DATEADD(m, 1, DATEFROMPARTS(@year, @month, 1)), 'yyyyMM')

这是小提琴

Answer 2

Assuming these are numbers, you can use arithmetic:

where yearmonth = ((@year * 12 + @month + 1) / 12) * 100 +
                   (@year * 12 + @month + 1) % 12
                  )

If it is a string, you can convert.