Python - break out into first while loop?

Question

Alright, I have a while loop based on an input here -

username = str(input('whats your favorite word? (enter to quit)')).strip().lower()
while(len(username) > 0):
    counter = 0
    for c in username:
        if(c == 'a' or c == 'e' or c == 'i' or c == 'u' or c == 'o'):
            counter+=1
    ending = 'vowels' if counter > 1 else 'vowel'
    print(f"word has {counter} {ending}!")
    break

After printing number of vowels I need to break out and prompt for a new username. But break results in the program exiting, and continue infinitely repeats the last print.

How can I break out back to the first input?

Answer 1

Include the first input in the loop:

username = str(input('whats your favorite word? (enter to quit)')).strip().lower()
while(len(username) > 0):
    counter = 0
    for c in username:
        if(c == 'a' or c == 'e' or c == 'i' or c == 'u' or c == 'o'):
            counter+=1
    ending = 'vowels' if counter > 1 else 'vowel'
    print(f"word has {counter} {ending}!")
    username = str(input('whats your favorite word? (enter to quit)')).strip().lower()

The program will end when you give no input (press enter directly)

Answer 2

If you want to repeat getting usernames, then that statement has to be within a loop. One standard way is to repeat that code at the bottom of your loop.

username = str(input('whats your favorite word? (enter to quit)')).strip().lower()
while(len(username) > 0):
    counter = 0
    for c in username:
        if(c == 'a' or c == 'e' or c == 'i' or c == 'u' or c == 'o'):
            counter+=1
    ending = 'vowels' if counter > 1 else 'vowel'
    print(f"word has {counter} {ending}!")
    # Get another username
    username = str(input('whats your favorite word? (enter to quit)')).strip().lower()

Answer 3

You need to get another user input inside the loop :

username = str(input('whats your favorite word? (enter to quit)')).strip().lower()
while(len(username) > 0):
    counter = 0
    for c in username:
        if(c == 'a' or c == 'e' or c == 'i' or c == 'u' or c == 'o'):
            counter+=1
    ending = 'vowels' if counter > 1 else 'vowel'
    print(f"word has {counter} {ending}!")
    username = str(input('whats your favorite word? (enter to quit)')).strip().lower() # Here!

Answer 4

I'd use if and break inside loop:

while True:
    username = str(input('whats your favorite word? (enter to quit)')).strip().lower()
    if not username:  # check if username is an empty string
        break
    # calculations and print are here