Capturing the exit code of sourced shell script without breaking the current script

Question

I have two shell scripts:

test.sh

function func() {
echo $1
exit 1
}

run.sh

source ./test.sh

func "Hello"
exitCode=$?
echo "Output: ${exitCode}"

Result:

Hello

The current problem which I'm facing is that when the function func returns 1, my run.sh script breaks and nothing gets executed after it. So, is there any way I can effectively capture the exit code without breaking run.sh. Since I can't modify the test.sh script, I have to find a way to do it in my run.sh. I tried using flock to execute the script but I couldn't get it working.

Answer 1

If you don't need environmental changes, you can run the function in a subshell. This makes the exit apply only to the ( .. ) and not your main script:

source ./test.sh

( func "Hello" )
exitCode=$?
echo "Output: ${exitCode}"