SQL How to search text field for 2nd without matching 22nd, etc?

Question

我想查询可以出现在文本列中任何位置的编号街道名称，并过滤掉具有更多数字的编号街道名称的匹配项，即2nd但不是42nd 、 182nd等。 有没有比组合更优雅或简化的方法：

WHERE col LIKE '2nd%' OR col LIKE '% 2nd%'

Answer 1

As long as the 2nd doesn't occur at the beginning of the string, you can just check that the character before it is not a digit using

col LIKE '%[^0-9]2nd%'

For example:

select col, case when  col like '%[^0-9]2nd%' then 'second' else 'not' end as test
from (values ('12 2nd st'), ('45 42nd st'), ('128 22nd st')) test(col)

Output:

col             test
12 2nd st       second
45 42nd st      not
128 22nd st     not

Answer 2

Nick's answer is very good, but it doesn't handle the case when '2nd' appears at the beginning of a string. This is easily handled by pre-pending a character on the column being compared:

' ' + col LIKE '%[^0-9]2nd%'