How can I get the correct ascii values?

Question

I am trying to convert a given string into its ascii numerical value. My input will be coordinates such as "A1", "H3", "E8" etc.

This is my code:

public static void main(String[] args) {
        String s = args[0];
        char [] charArray = s.toCharArray();
        int ascii = 0;
        for (int i = 0; i < charArray.length; i ++) {
            ascii = ascii + Character.getNumericValue(charArray[i]);
        }
    }

I was expecting the output for A1 to be 114 since (int) 'A' = 65 and (int) '1' = 49, however I am getting the result 11 for A1. How can I fix this?

Answer 1

Character.getNumericValue won't give you the ascii representation of the character.

A char is just a positive 16-Bit integer containing the numeric representation of the character.

Therefore, you can just add the char to the int ( ascii+=charArray[i]; ).

[ Note ]

A char represents a Unicode-1 character and not an ascii character but it is backwards compatible.

Answer 2

I am trying to convert a given string into its ascii numerical value. My input will be coordinates such as "A1", "H3", "E8" etc.

This is my code:

public static void main(String[] args) {
        String s = args[0];
        char [] charArray = s.toCharArray();
        int ascii = 0;
        for (int i = 0; i < charArray.length; i ++) {
            ascii = ascii + Character.getNumericValue(charArray[i]);
        }
    }

I was expecting the output for A1 to be 114 since (int) 'A' = 65 and (int) '1' = 49, however I am getting the result 11 for A1. How can I fix this?