Hello I have a dataframe where I want to remove a specific set of characters 'fwd' from every row that starts with it. The issue I am facing is that the code I am using to execute this is removing anything that starts with the letter 'f'.
my dataframe looks like this:
summary
0 Fwd: Please look at the attached documents and take action
1 NSN for the ones who care
2 News for all team members
3 Fwd: Please take action on the action needed items
4 Fix all the mistakes please
When i used the code:
df['Clean Summary'] = individual_receivers['summary'].map(lambda x: x.lstrip('Fwd:'))
I end up with a dataframe that looks like this:
summary
0 Please look at the attached documents and take action
1 NSN for the ones who care
2 News for all team members
3 Please take action on the action needed items
4 ix all the mistakes please
I don't want the last row to lose the F in 'Fix'.
You should use a regex
remembering ^
indicates startswith:
df['Clean Summary'] = df['Summary'].str.replace('^Fwd','')
Here's an example:
df = pd.DataFrame({'msg':['Fwd: o','oe','Fwd: oj'],'B':[1,2,3]})
df['clean_msg'] = df['msg'].str.replace(r'^Fwd: ','')
print(df)
Output:
msg B clean_msg
0 Fwd: o 1 o
1 oe 2 oe
2 Fwd: oj 3 oj
You are not only loosing 'F'
but also 'w'
, 'd'
, and ':'
. This is the way lstrip
works - it removes all of the combinations of characters in the passed string.
You should actually use x.replace('Fwd:', '', 1)
1 - ensures that only the first occurrence of the string is removed.
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