The total number of words in this string is 11. But my code returns 13.
var txt = "Helllo, my -! This is a great day to say helllo.\n\n\tHelllo! 2 3 4 23";
txt = txt.replace(/[0-9]/g, '');
var words_count = txt.match(/\S+/g).length;
\\S+
will match any non-space character, which will include substrings like -!
. You might match sequences of non-space characters which also include at least one alphabetical character in them, with \\S*[az]\\S*
:
var txt = "Helllo, my -! This is a great day to sayhelllo.\\n\\n\\tHelllo! 2 3 4 23"; console.log(txt.match(/\\S*[az]\\S*/gi).length);
If you can count on what you want to count as a "word" to start with an alphabetical character, you can remove the leading \\S*
.
If you want to make the trailing \\S*
more restrictive, you could whitelist a list of permitted characters inside "words", like '
if you want:
var txt = "Helllo, my -! This is a great day to sayhelllo.\\n\\n\\tHelllo! 2 3 4 23"; console.log(txt.match(/[az][a-z']*/gi).length);
(to add more characters to the whitelist, just expand the [a-z']
character set to whatever you need)
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