Trying to find the pandas equivalent for the following SQL:
SELECT KnownSince, COUNT(1)
FROM mytable
GROUP BY KnownSince
I have already tested:
aux.groupby(['KnownSince'])['KnownSince'].agg(['count']),
aux.groupby(['KnownSince']).agg(['count']),
aux['KnownSince'].groupby(['KnownSince']).agg(['count']),
aux['KnownSince'].groupby().agg(['count'])
But didn't achieve expexted result.
PS: KnownSince
is a number in the format YYYYMM and not a datetime object.
It's size
:
df.groupby('KnownSince', as_index=False).size()
Or named agg
:
df.groupby('KnownSince').agg(count=('KnownSince','count')).reset_index()
在pandas
,内置函数value_counts
df['KnownSince'].value_counts()
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