const Arri = JSON.parse(data);
var pname;
for (var i = 0; i < Arri.length; i++) {
pname = " " ; // null tried
var propinfo = Arri[i].propinfo;
for (var j = 0; j < propinfo.length; j++) {
pname = pname +propinfo[j].propertyname +" | ";
}
$('#tblbody').append('<tr><td scope="row">'+Arri[i].propertyid+'</td><td>'+pname+'</td></tr>"');
}
when I run this code I have the following output.
pro1 | pro2 | Pro3
pro1 | pro2 | Pro3 pro4 | pro5 | Pro6
pro1 | pro2 | Pro3 pro4 | pro5 | Pro6 pro7 | pro8 | Pro9
pro1 | pro2 | Pro3 pro4 | pro5 | Pro6 pro7 | pro8 | Pro9 pro10 | pro11 | Pro12
I want to be like it:
pro1 | pro2 | Pro3
pro4 | pro5 | Pro6
pro7 | pro8 | Pro9
pro10 | pro11 | Pro12
Have you try NULL instead of double quoutation,
const Arri = JSON.parse(data);
var pname;
for (var i = 0; i < Arri.length; i++) {
pname = NULL;
var propinfo = Arri[i].propinfo;
for (var j = 0; j < propinfo.length; j++) {
pname = pname +propinfo[j].propertyname +" | ";
}
$('#tblbody').append('<tr><td scope="row">'+Arri[i].propertyid+'</td><td>'+pname+'</td></tr>"');
}
lets try local variables. try this:
const Arri = JSON.parse(data);
for (let i = 0; i < Arri.length; i++) {
let pname = "" ; // null tried
let propinfo = Arri[i].propinfo;
for (let j = 0; j < propinfo.length; j++) {
pname = pname +propinfo[j].propertyname +" | ";
}
$('#tblbody').append('<tr><td scope="row">'+Arri[i].propertyid+'</td><td>'+pname+'</td></tr>"');
}
这段代码没有任何问题,我确定你的json有问题,你能分享你的json数据吗?
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