Selenium : How to wait then click?

Question

I'm using selenium for automation and i want to click in each one of the <ul> elements then wait before clicking again in the element. This is my code but it doesn't seem to be the solution :

def navBar():
 driver=setup()
 navBar_List = driver.find_element_by_class_name("nav")
 listItem = navBar_List.find_elements_by_tag_name("li")
 for item in listItem :
    WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.TAG_NAME,"li")))
    item.click()

Here the HTLM code :

<ul class="nav navbar-nav"> 
                <li tabindex="0">
                        <a class="h">
                            <div class="icon-left-navbar">
                                 ...
                            </div>
                        </a>
                    </li>
                    <li tabindex="0">
                        <a class="h">
                            <div class="icon-left-navbar">
                                 ...
                            </div>
                        </a>
                    </li>
                    <li tabindex="0">
                        <a class="h">
                            <div class="icon-left-navbar">
                                 ...
                            </div>
                        </a>
                    </li>
                </ul>

Answer 1

Define your li with .find_elements .

Use xpath for recognize them : //ul[@class='nav navbar-nav']//li .

With loop you can utilize increment to wait each li . I'm imagine it will produce like below:

(xpath)[1]
(xpath)[2]
etc...

And try the following code:

listItem = WebDriverWait(driver, 30).until(EC.visibility_of_all_elements_located((By.XPATH,"//ul[@class='nav navbar-nav']//li")))

for x in range(1, len(listItem)+1):
    WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"(//ul[@class='nav navbar-nav']//li)[" +str(x) +"]"))).click()

Answer 2

Thread.sleep(100)是一个选项吗？