How can convert number given in parenthesis with negative number in python?

Question

I have a column with rows having a string like:

{"Manufacture":"1920","Comapany":"(BMW)","Loss":"(20)","price":"93"}
{"Manufacture":"1911","price":"20","shutdown":"(13)"}

I want to convert (number) entry with -number for example in first-row entry output will be

{"Manufacture":"1920","Comapany":"(BMW)","Loss":"-20","price":"93"}

Entry for loss is (20) which is converted to -20

same goes for second row entry

{"Manufacture":"1911","price":"20","shutdown":"-13"}

Answer 1

Try:

re.sub(r"\((\d+)\)", r"-\1", s)

---

Example:

s = str({"Manufacture":"1920","Comapany":"(BMW)","Loss":"(20)","price":"93"})
st = str({"Manufacture":"1911","price":"20","shutdown":"(13)"})

---

res = re.sub(r"\((\d+)\)", r"-\1", s)

---

res:

"{'Manufacture': '1920', 'Comapany': '(BMW)', 'Loss': '-20', 'price': '93'}"

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result = re.sub(r"\((\d+)\)", r"-\1", st)

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result:

"{'Manufacture': '1911', 'price': '20', 'shutdown': '-13'}"

Edit:

Let say your df is:

     0
0   {"Manufacture":"1920","Comapany":"(BMW)","Loss":"(20)","price":"93"}
1   {"Manufacture":"1911","price":"20","shutdown":"(13)"}

---

def num2neg(row):
    return re.sub(r"\((\d+)\)", r"-\1", row)

df[0] = df[0].apply(num2neg)

---

df:

    0
0   {"Manufacture":"1920","Comapany":"(BMW)","Loss":"-20","price":"93"}
1   {"Manufacture":"1911","price":"20","shutdown":"-13"}