how to get first K smallest number in a dictionary

Question

For example, I have a dictionary

dicts["A"] = 1
dicts["B"] = 2
dicts["C"] = 3 # .....etc, 

if I want to get the first 2 key, ie "A" and "B" based on their values, ie 1 and 2, what should I do? Thanks in advance.

Answer 1

Try:

#lets say
dic={'A':2,'B':1, 'C':5}
#sorting the dict
dic = {k: v for k, v in sorted(dic.items(), key=lambda item: item[1])}

Now that the dictionary is sorted, iterate through it. To find K smallest Values:

k = K
for i in range(k):
    print([k[0] for k in dic.items()][i])

Therefore, shortly:

k = K
for i in range(k):
    print([k[0] for k in {k: v for k, v in sorted(dic.items(), key=lambda item: item[1])}.items()][i])

As a One-Liner:

k = K
dic={'A':2,'B':1, 'C':5}
print('\n'.join([k[0] for k in {k: v for k, v in sorted(dic.items(), key=lambda item: item[1])}.items()][i] for i in range(k)))

Answer 2

dic={'A':1,'B':2, 'C': 3}
k = 2
[y[0] for y in sorted(dic.items(), key = lambda x: x[1])[:k]]

The last line sort the dictionary items according to the key ( x[1] ), then take the first k items ( [:k] ) and then extract only the keys ( y[0] ).