Output to fetch in single row

Question

Example:

Reporter = driver.find_element_by_xpath("/html/body/div[1]/section/div[1]/div[3]/div/div/div/div/div/div/div[2]/div/issuetable-web-component/table/tbody/tr[" + p + "]/td[5]/span/a").get_attribute('rel')

s = Reporter

Output:

user1
user2

Expected:

user1,user2

Answer 1

You could try to format that output:

your_string = """
user1
user2
"""

If you need it as a tuple like your comment:

new_tuple = tuple(your_string.strip().splitlines())

Or as a string:

",".join([str(x) for x in your_string.strip().splitlines()])

Answer 2

Considering your loop is filling Reporter which is a list of Strings

    Reporter = driver.find_element_by_xpath("/html/body/div[1]/section/div[1]/div[3]/div/div/div/div/div/div/div[2]/div/issuetable-web-component/table/tbody/tr[" + p + "]/td[5]/span/a").get_attribute('rel')


   // joins elements of Reporter by ',' and stores in sting s 
    s = ","
    s = s.join(Reporter)

Answer 3

Maybe try the following and check -

s = s.replace('\n', ',')