how to pass the most recent file from a directory to awk input file?

Question

It should be something like that:

    awk '

       ...

     ' ls -rt | tail -n 1

"ls -rt | tail -n 1" is the name of the most recent file from a directory

Thank you in advance

Answer 1

You can use format mentioned below, please choose separtor and required field to print as per your 'ls -lr' output.

 ls -lr <directoryName|*>| tail -n 1|awk -F<separator> '{ print $<tokenNumber> }'

Example:

ls -lr cpas| tail -n 1|awk -F: '{ print $2 }'