Remove all special characters from the end of a string

Question

I am currently developing an app which requires multiple special characters at the end of the string.

Some examples are:

1. 5 * + -
2. 345-+
3. ABC+-++

etc.

I would like to replace all these as follows:

1. 5*+- to 5A
2. 345-+ to 345A
3. ABC+-++ to ABCA

Can someone help me in doing this?

Thanks!

Answer 1

Use the String.prototype.replace() method.

var str = 'Your string';
var regex = 'Your regex';
str.replace(regex, 'replaced by this string');

Answer 2

Java version of code:

    String myName ="5 ABCD898* + -";
        char[] line = myName.toCharArray();
        for(int i = line.length-1; i>=0; i--)
    {
        if (!((line[i] >= 'a' && line[i]<='z') || (line[i] >= 'A' && line[i]<='Z')||(line[i] >= '0' && line[i]<='9')))
        {
            line[i] = ' ';
        }else{
break;}
    }
    myName=String.valueOf(line).trim()+"A";
System.out.println(myName);

other version of code

string line="5 * + -";

for(int i = line.size()-1; i>=0; i--)
    {
        if (!((line[i] >= 'a' && line[i]<='z') || (line[i] >= 'A' && line[i]<='Z')||(line[i] >= '0' && line[i]<='9')))
        {
            line[i] = '\0';
        }else{
break;}
    }
line+="A";

Answer 3

You can use String.prototype.replace() with callback which will help you modify the string

 const inputs = ['5*+-', '345-+', 'ABC+-++']; const results = inputs.map(s => { const specialChr = /[^A-Za-z0-9 ].*/g; const output = s.replace(specialChr, function (matched, index, original) { return matched + original.slice(0, index) + 'A'; }); return output; }); console.log(results);

Answer 4

Fastest for you, split on first special char and get the first .

const clean = (str) => str.split(/\W/)[0]+"A"

 const clean = (str) => str.split(/\W/)[0]+"A" const data = `5*+- to 5A 345-+ to 345A ABC+-++ to ABCA`.split("\n") data.forEach(line => console.log(clean(line)))

Answer 5

Depends what you mean by "special characters". I'd suggest a RegEx approach. Start off by looking at W3Schools