Find all the elements of a list whose field match with a value

Question

If I have a list like this:

[element(name='A', value=0), element(name='B', value=1)]

I would like to find all the element of the list whose value field is equal to 0:

element[:].value == 0

Which would the shortest way?

Answer 1

elements = [element(name='A', value=0), element(name='B', value=1)]
matches = [element for element in elements if element.value == 0]

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To get the names from all the matches:

names = [element.name for element in matches]
print(names)

Answer 2

A list comprehension should do the trick

not_values = [e for e in elements if not e.value] 

Please note I'm using not e.value because I think it reads better and it's more coherent with the variable name not_values but you could also use e.value == 0 .