The purpose of this code is to validate a name and print each word with the 1st letter capitalize. I mean if the name inserted contains one of the char that are inside Invalid_Name
it's not valide.
It works properly, but when I try to print that name, it starts from the 2nd letter. Just look at the code below(sorry for the size):
void validate_charName()
{
int i = 0;
int check = 0;
string Invalid_Name = "1234567890'!\"£$%&/()=?^*-+<>-.,_:;[]{}°@§";
bool name_is_valide = true;
// Validate the character's name
while(name_is_valide)
{
bool invalid_name = false;
name_is_valide = true;
cout<< "\nWhat's the name of your character? " << endl;
cin.ignore();
getline(cin, char_name);
for(int i = 0; i < char_name.length(); i++)
{
for(int j = 0; j < Invalid_Name.length(); j++)
{
if(char_name[i] == Invalid_Name[j])
invalid_name = true;
}
}
if(invalid_name)
cout<< "The name must contains only letters!" << endl;
else
name_is_valide = false;
}
while(char_name[i])
{
if(check == 0)
{
char_name[i] = toupper(char_name[i]);
check = 1;
}
else if(isspace(char_name[i]))
check = 0;
i++;
}
sleepcp(1000);
cout << " ******Your character's name is " + char_name + "****** " << endl;
}
If I insert the name "edward kenway" it will print out "Dward Kenway"
, even if I write i = 0;
before the loop.
Why?
*************EDIT*************
If i print the name in the right way since the first input, it works. Otherwise, it gives me that problem.
I solved this just putting "cin.sync()" before "getline()". Hope that can helps someone.
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